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Q.

The potential due to the electric dipole (length of dipole = 2a) at a distance r from the dipole on the axial line

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a

14πϵ0qar2

b

14π∈04qar2

c

14πϵ02qar2

d

Zero

answer is A.

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Detailed Solution

Vaxial=14πε0qr−a−qr+a=14πε02qar2

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The potential due to the electric dipole (length of dipole = 2a) at a distance r from the dipole on the axial line