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Q.

The potential energy (in joule) of a body of mass 2kg moving in the XY-plane is given by U = 6x + 8y, where x and y are in meters. If the body is at rest at point (6m, 4m) at time t = 0, it will cross y-axis at time t equal to.

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a

2s

b

4s

c

3s

d

2s

answer is B.

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Detailed Solution

detailed_solution_thumbnail

Fx=-∂U∂x=-6

and

Fy=-∂U∂y=-8

Now, Fx=max⇒ax=-62=-3 m/s2

When it will cross y − axis at that time x will be zero

Using, x=ut+12axt2

0-6=0-12×3×t2

t=2 s

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