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Q.

The potential energy of a certain spring when stretched from natural length through a distance of 0.3 m is 5.6 J. Find the amount of work in joule that must be done on this spring to stretch it through an additional distance of 0.15m.

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answer is 7.

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Detailed Solution

Ui=12kx2

5.6=12k(0.3)2

k=11.20.09

Uf=12kx+x02

=12×11.20.09(0.45)2=12.6 J

W=Uf-Ui=12.6-5.6=7J

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