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Q.

The Potential energy of a long spring when stretched by 2 cm is U. If the spring is stretched by 8cm, potential energy stored in it will be:

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a

8U

b

2 U

c

16 U

d

4U

answer is A.

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Detailed Solution

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 U=12kx2 U1=12k(2)2 U2=12k(8)2 U2U1=8222=16 U2=16U1=16U

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