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Q.

The potential energy of a particle is determined by the expression U=αx2+y2, where α is a positive constant. The particle begins to move from a point with coordinates (3, 3), only under the action of potential field force. Then its kinetic energy T at the instant when the particle is at a point with the coordinates (1, 1) is

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a

24α

b

8α

c

Zero

d

16α

answer is C.

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Detailed Solution

As the particle moves only under the action of conservative force, its mechanical energy must be conserved. So ΔT+ΔU=0 (T stands for kinetic energy)

ΔT=ΔU=UiUf=α32+32α12+12=16α

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