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Q.

The potential energy of a particle of mass 1 kg in motion along the x – axis is given by 
U = 4(1 – cos 2x)J
Here, x is the meter. The period of small oscillations (in second) is

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a

2π

b

π

c

π2

d

2π

answer is C.

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Detailed Solution

F=dUdx=8sin2x
a=Fm=8sin2x
For small oscillations sin2x = 2x
i.e.,                    a = - 16x
Since  ax
Oscillations are simple harmonic in nature
T=2πxa=2π116=π2s

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