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Q.

The potential energy of a particle of mass m is given by U(x)=E0;0x10;x>1  .  λ1 and λ2 are the de Broglie wavelengths of the particle, when 0  x  1 and x > 1 respectively. If the total energy of particle is 2E0,the ratio λ1λ2 will be 

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a

2

b

1

c

2

d

12

answer is C.

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Detailed Solution

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K.E=2E0E0=E0( for 0x1) λ1=h2mE0

 K.E. =2E0( for x>1) λ2=h4mE0 λ1λ2=2

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