The potential energy of a particle of mass m is given by 

$U\left(x\right)=\left\{\begin{array}{l}{E}_0;0\le x\le 1\\ 0;x>1\end{array}\right.$

${\mathrm{\lambda }}_1 \text{and }{\mathrm{\lambda }}_2$ are the de-Broglie wavelengths of the particle, when $\mathbf{0}\le \mathrm{x}\le 1 \text{and }\mathrm{x}>1$ respectively. If the total energy of particle is $2E_0$, the ratio $\frac{{\lambda }_1}{{\lambda }_2}$ will be