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Q.

The potential energy of a particle under a conservative force is given by Ux=x2−3xJ. The equilibrium position of the particle is at
 

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a

x=2.5m

b

x=1.5m

c

x=3m

d

x=2m

answer is A.

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Detailed Solution

Ux=x2−3xJ

For a conservative field, Force F=−dudx

∴F=−ddxx2−3x=−2x−3=−2x+3

At equilibrium position, F=0
 ⇒−2x+3=0⇒x=32m=1.5m

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