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Q.

The potential energy of the electron present in the ground state of ${Be}^{3 +}$ ion is represented by:

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a

$- \frac{e}{π ϵ_{0} r}$

b

$- \frac{e^{2}}{π ϵ_{0} r}$

c

$+ \frac{e^{2}}{π ϵ_{0} r}$

d

$- \frac{e^{2}}{π ϵ_{0} r^{2}}$

answer is D.

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Detailed Solution

The value of potential energy;

$P E = - \frac{e \times 4 e}{4 π ε_{0} \times r} = - \frac{e^{2}}{π ε_{0} r}$

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