The power of the lens having a focal length of 1 cm is:

The lens power is equal to the inverse of the focal length in meters. The unit of power is $m^{-1}$ OR dioptre ($\mathrm{D}$).

Power, $\text{P=}\frac{1}{\text{f}}$

Where $\mathrm{f}$ is the lens's focal length

Given that:

The lens's focal length $\text{f=100 cm=}\frac{1}{100}\text{=0.01 m}$

As a result, the lens's power, 

$\begin{array}{rcl} & & \text{P=}\frac{1}{\text{f}}\\ & & \text{=}\frac{1}{0.01}\\ & & \text{=100 D}\end{array}$

Hence option (C) is correct.