The present age of Shrikant is $\frac{3}{2}$ times the present age of Anand. Six years ago, the product of their age was 72. How can this situation be represented mathematically? 

Let the present age of Anand be x years. Then, Shrikant’s present age = $\frac{3}{2}\mathrm{x}$ years 

Six years ago, Anand’s age was (x − 6) years whereas Shrikant’s age was $(\frac{3}{2}\mathrm{x} - 6)$ years. 

By the given condition, 

$\left(\mathrm{x}-6\right)\left(\frac{3}{2}\mathrm{x}-6\right)=72$ 

$\Rightarrow \frac{3}{2}{\mathrm{x}}^2-9\mathrm{x}-6\mathrm{x}+36=72$ 

$\Rightarrow \frac{3}{2}{\mathrm{x}}^2-15\mathrm{x}-36=0$ 

$\Rightarrow {\mathrm{x}}^2-10\mathrm{x}-24=0$ 

This equation represents the given situation.