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Q.

The pressure at depth h below the surface of a liquid of density ρ open to the atmosphere is

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a

equal to the atmospheric pressure

b

increases exponentially with depth

c

less than the atmospheric pressure by  ρgh

d

greater than the atmospheric pressure by ρgh 

answer is A.

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Detailed Solution

The pressure at depth h below the surface of a liquid of density ρ open to the atmosphere is P=Pa+ρgh, where Pa is the atmospheric pressure. Thus, pressure P at depth h below the surface of a liquid open to the atmosphere is greater than the atmospheric pressure by an amount ρgh.

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