The pressure exerted by 1023 gas-molecules, each of mass 10-25 kg, in a container of volume, 1x10-3 m3 and having root mean square velocity of 103 ms-1.

p=13×m x N x u2v=1×10−25×1023×10323×10−3=3.33×106Nm−2

The pressure exerted by 1023 gas-molecules, each of mass 10-25 kg, in a container of volume, 1x10-3 m3 and having root mean square velocity of 103 ms-1.

p=13×m x N x u2v=1×10−25×1023×10323×10−3=3.33×106Nm−2

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The pressure exerted by 10²³gas-molecules, each of mass 10^-25 kg, in a container of volume, 1x10^-3m³ and having root mean square velocity of 10³ ms^-1.

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3.33x10⁷ N/m²

3.33x10⁶N/m²

6.66x10⁶ N/m²

6.66x10⁷ N/m²

answer is B.

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Detailed Solution

$p = \frac{1}{3} \times \frac{m x N x u^{2}}{v} = \frac{1 \times 10^{- 25} \times 10^{23} \times {(10^{3})}^{2}}{3 \times 10^{- 3}} = 3 .33 \times 10^{6} {Nm}^{- 2}$

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The pressure exerted by 1023 gas-molecules, each of mass 10-25 kg, in a container of volume, 1x10-3 m3 and having root mean square velocity of 103 ms-1.

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The pressure exerted by 10²³gas-molecules, each of mass 10^-25 kg, in a container of volume, 1x10^-3m³ and having root mean square velocity of 10³ ms^-1.