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The pressure of a definite mass of a gas is directly proportional to the temperature and inversely proportional to the volume under the given conditions. If temperature is increased by 40% and volume is decreased by 20% then the new pressure will be?

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Be increased by 75%

Reduce to 25%

Be increased by 20%

Increased by 28%

answer is A.

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Detailed Solution

Given,
Temperature increases =

40 %

.
Pressure increases =

40 %

(By the question)
Let pressure is 100. Then,
New pressure:

= 100 + \frac{100 \times 40}{100}

= 140

When,
Volume decreases with

20 %

then,
Pressure increases with

20 %

(Inversely proportional)
So, new pressure,

= \frac{140}{\frac{100 - 20}{100}}

= \frac{140 \times 100}{80}

= 175

So, % pressure increased,

175 - 100 = 75 %

Hence, option 1 is correct.

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