The pressure of a gas filled in the bulb of a constant volume gas thermometer at 00C and 1000C are 28.6 cm and 36.6 cm of mercury respectively. The temperature of bulb at which pressure will be 35.0 cm of mercury will be

t∘=Xt−X0X100−X0×100t=35−28.636.6−28.6×100=640∘8=80∘C

The pressure of a gas filled in the bulb of a constant volume gas thermometer at 00C and 1000C are 28.6 cm and 36.6 cm of mercury respectively. The temperature of bulb at which pressure will be 35.0 cm of mercury will be

t∘=Xt−X0X100−X0×100t=35−28.636.6−28.6×100=640∘8=80∘C

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The pressure of a gas filled in the bulb of a constant volume gas thermometer at 0⁰C and 100⁰C are 28.6 cm and 36.6 cm of mercury respectively. The temperature of bulb at which pressure will be 35.0 cm of mercury will be

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70⁰C

55⁰C

40⁰C

80⁰C

answer is A.

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Detailed Solution

$\begin{array}{l} t^{\circ} = \frac{(X_{t} - X_{0})}{X_{100} - X_{0}} \times 100 \\ t = (\frac{35 - 28 .6}{36 .6 - 28 .6}) \times 100 \\ = \frac{640^{\circ}}{8} = 80^{\circ} C \end{array}$

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