The pressure of a gas filled in the bulb of a constant volume gas thermometer at 0^oC and 100^oC are 28.6 cm and 36.6 cm of mercury respectively. The temperature of bulb at which pressure will be 35.0 cm of mercury will be

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80^oC

70^oC

55^oC

40^oC

answer is A.

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Detailed Solution

Temp $\to$ Pressure
0^oC $\to$ P₀ = 28.6cm of Hg
100^oC $\to$ P₁₀₀ = 36.6cm of Hg
t^oC $\to$ P_t = 35cm of Hg
we have
$t = (\frac{P_{t} - P_{0}}{P_{100} - P_{0}}) x 100^{0} C = (\frac{35 - 28.6}{36.6 - 28.6}) x 100 = 80^{o} C$

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