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Q.

The pressure of a given mass of gas at 27^oC is 75 cm of mercury. Find the temperature in ^oC at which the pressure is doubled, the gas being heated at constant volume.

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a

420^oC

b

327^oC

c

627^oC

d

227^oC

answer is B.

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Detailed Solution

t₁ = 27^oC $\Rightarrow$ T₁ = 300 k ; P₁ = 75cm of Hg
P₂ = 2P₁ = 2(75) = 150 of Hg
t₂ = ?
At constant volume, from charles law
$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}} \Rightarrow \frac{75}{300} = \frac{150}{T_{2}}$
T₂ = 600k = 327^oC

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