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Q.

The pressure of a moist gas at 27°C is 4 atm. The volume of the container is doubled at the same temperature. The new pressure of the moist gas is …. ×10–1 atm. (Nearest integer)

(Given : The vapour pressure of water at 27°C is 0.4 atm)

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answer is 22.

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Detailed Solution

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Pgas0+VP.=4

Pgas0=40.4=3.6

As volume is doubled, Pgasnew=1.8 atm

New Total Pressure = 1.8 + 0.4 = 2.2 atm

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