Q.

The pressure of a monoatomic gas increases linearly from 4×105 Pa to 8×105 Pa when its volume increases from 0.2 m3 to  0.5m3 then  increase in internal energy in  joule is 

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a

4.8×104

b

2.4×105

c

4.8×105

d

6.8×104

answer is A.

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Detailed Solution

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Change in internal energy of a gas is given by U =nCvdT= nRγ-1T2-T1=P2V2-P1V1γ-1

 As the gas is monoatomic, g = 5/3 

            So U=1058×0.5-4×0.253-1=32×3.2×105=4.8×105

 

       

 

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