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The pressure of $H_{2}$ that would be required to make the EMF of a hydrogen electrode zero when immersed in pure water at $25^{\circ} C$ is $10^{x}$ bar. The value of x is ___________

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answer is -14.

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Detailed Solution

$H_{2} (g) ⇌ {2H}^{+} (a q .) + 2 e^{-}$

$E_{c e l l} = E_{c e l l}^{\circ} - \frac{0.0591}{n} \log \frac{{[H^{+}]}^{2}}{p_{H_{2}}}$

$0 = 0 - \frac{0591}{2}$ $\log \frac{{(10^{- 7})}^{2}}{p_{H_{2}}}$

$p_{H_{2}} = 10^{- 14} b a r$

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