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Q.

The pressure of water in a pipe when tap is closed is 5.5 X 105 Nm-2. When tap gets open, pressure reduces to 5 X 105 Nm-2. The velocity with which water comes out on opening the tap is

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a

10 ms-1

b

5 ms-1

c

15 ms-1

d

20 ms-1

answer is A.

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Detailed Solution

Given,    p1=5.5×105Nm−2 and p2=5×105Nm−2

∴   Δp=p1−p2=(5.5−5)×105

= 0.5 x 105 Nm-2.

Decrease in pressure energy == Increase in kinetic energy

or   Δp=12ρv2

∴ v=2(Δp)ρ=2×0.5×105103=10ms−1

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