Q.

The pressure of water in a water pipe when tap it opened and closed respectively 3×105N/m2 and 3.5×105N/m2. With open tap the velocity of water flowing is :

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a

20 m/s

b

5 m/s

c

15 m/s

d

10 m/s

answer is A.

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Detailed Solution

P1+12ρv12=P2+12ρv22P1P2=12ρv22

Since tap is closed, v1 = 0

3.5×1053×105=12×103×v2v=10m/s

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