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The pressure (P) and temperature (T) relationship of an ideal gas obeys the equation $P T^{2} =$ constants. The volume expansion coefficient of the gas will be:

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$\frac{3}{T^{2}}$

$3 T^{2}$

$\frac{3}{T^{3}}$

$\frac{3}{T}$

answer is C.

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Detailed Solution

$P T^{2} = c o n s \tan t; \frac{n R T}{V} T^{2} =$ constant
$\Rightarrow V = K T^{3}; γ = \frac{1}{V} \frac{d v}{d T} = \frac{3}{T}$

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