The pressure variation that corresponds to pain threshold (i,e. the ear can tolerate in loud sound) is about 30 Pa. velocity of sound in water is 2×103 m/s. The intensity of sound wave produced in water corresponding to loud sound is (density of water is 103 kg per m3 )

Intensity of sound waves I=P022ρv=30×302×103×2×103=0.3×10−3W/m2

The pressure variation that corresponds to pain threshold (i,e. the ear can tolerate in loud sound) is about 30 Pa. velocity of sound in water is 2×103 m/s. The intensity of sound wave produced in water corresponding to loud sound is (density of water is 103 kg per m3 )

Intensity of sound waves I=P022ρv=30×302×103×2×103=0.3×10−3W/m2

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The pressure variation that corresponds to pain threshold (i,e. the ear can tolerate in loud sound) is about 30 Pa. velocity of sound in water is $\sqrt{2} \times 10^{3}$ m/s. The intensity of sound wave produced in water corresponding to loud sound is (density of water is $10^{3}$ kg per $m^{3}$ )

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$10^{3} W / m^{2}$

$0.3 \times 10^{- 3} W / m^{2}$

$1 W / m^{2}$

$10^{- 12} W / m^{2}$

answer is B.

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Detailed Solution

Intensity of sound waves $I = \frac{P_{0}^{2}}{2 ρ v}$
$= \frac{30 \times 30}{2 \times 10^{3} \times \sqrt{2} \times 10^{3}} = 0.3 \times 10^{- 3} W / m^{2}$

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The pressure variation that corresponds to pain threshold (i,e. the ear can tolerate in loud sound) is about 30 Pa. velocity of sound in water is 2×103 m/s. The intensity of sound wave produced in water corresponding to loud sound is (density of water is 103 kg per m3 )

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The pressure variation that corresponds to pain threshold (i,e. the ear can tolerate in loud sound) is about 30 Pa. velocity of sound in water is $\sqrt{2} \times 10^{3}$ m/s. The intensity of sound wave produced in water corresponding to loud sound is (density of water is $10^{3}$ kg per $m^{3}$ )