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Q.

The primary of a transformer with primary to secondary turns ratio of 1 : 2, is connected to an alternating of voltage 200 V.  A current of 4 A is flowing though the primary coil.  Assuming that the transformer has no losses, the secondary voltage and current are respectively

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a

100 V, 8 A

b

400 V, 8 A

c

100 V, 2A

d

400 V, 2 A

answer is C.

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Detailed Solution

εsεp=NSNPεS=21×200V=400V

ISIP=NPNSIS=12×4A=2A

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