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Q.

The principal organic product formed in the reaction given below is :
${CH}_{2} = CH {({CH}_{2})}_{8} COOH + HBr \overset{peroxide}{⟶} \dots$

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a

${CH}_{2} {BrCH}_{2} {({CH}_{2})}_{8} COOH$

b

${CH}_{2}^{'} = CH {({CH}_{2})}_{8} COBr$

c

${CH}_{3} - CHBr {({CH}_{2})}_{8} COOH$

d

${CH}_{2} = CH {({CH}_{2})}_{7} CHBrCOOH$

answer is C.

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