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Q.

The probabilities of A and B to pass an examination are 2/10,3/10. The probability that only one of them, to pass the examination is

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a

41/50

b

47/50

c

19/50

d

37/50

answer is C.

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Detailed Solution

$P (A) = 2 / 10, P (B) = 3 / 10, A, B$ are independent
$\begin{aligned} P [(A \cap \bar{B}) \cup \bar{(A} \cap B)] = P (A \cap \bar{B}) + P (\bar{A} \cap B) \\ = P (A) P (\bar{B}) + P (\bar{A}) P (B) \\ = \frac{2}{10} \times \frac{7}{10} + \frac{8}{10} \times \frac{3}{10} = \frac{38}{100} = \frac{19}{50} \end{aligned}$

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