The probabilities of three events A, B, C are given by $P\left(A\right) = 0.6, P\left(B\right) = 0.4 and P\left(C\right) = 0.5 .$ If $\mathrm{P}(\mathrm{A}\cup \mathrm{B})=0.8,\mathrm{P}(\mathrm{A}\cap \mathrm{C})=0.3,\mathrm{P}(\mathrm{A}\cap \mathrm{B}\cap \mathrm{C})=0.2, \mathrm{P}(\mathrm{B}\cap \mathrm{C})=\mathrm{\beta }$ and$\mathrm{P}(\mathrm{A}\cup \mathrm{B}\cup \mathrm{C})=\mathrm{\alpha }$where $\text{0.85≤α≤0.95 then β}$ lies in