Q.

The probability distribution of the random variable X is as follows:

X-3-2-10123
P(X)5k3kkkk2kk

If 2nd moment about origin of the random variable X is P, then 14P is______

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answer is 76.

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Detailed Solution

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ΣP(X=xi)=1   k=114

P= 2nd moment about origin =E(x2)=Σxi2P(X=xi)

  P=76k14P=76

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