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Q.

The probability of an ordinary year having 53 Tuesdays is:

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a

\frac{2}{7}

b

\frac{1}{7}

c

\frac{3}{7}

d

\frac{4}{7}

answer is B.

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Detailed Solution

1 year = 365 days
A year has 52 weeks. Hence there will be 52 Tuesdays for sure.
52 weeks = 52×7= 364 days
365−364= 2 days
In an ordinary year, there will be 52 Tuesdays and 1 day will be left.
This 1 day can be:
Sunday
Monday
Tuesday
Wednesday
Thursday
Friday
Saturday
Of these total 7 outcomes, the favorable outcomes are 1.
Hence the probability of getting 53 Tuesdays in an ordinary year is =

\frac{1}{7}

.
Hence 2 is the correct option.

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