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Q.

The probability that a bomb dropped from a plane strikes the target is $\frac{1}{5}$ . The probability that out of six bombs dropped at least 2 bombs strike the target is

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a

0.345

b

0.246

c

0.543

d

0.426

answer is A.

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Detailed Solution

Given that : $p = \frac{1}{5}, q = \frac{4}{5}$ ,n=6

$P (X \geq 2) = 1 - [P (X = 0) + P (X = 1)]$

= $1 - [6_{C_{0}} {(\frac{4}{5})}^{6} + 6_{C_{1}} (\frac{4}{5}) {(\frac{1}{5})}^{4}]$

= $0.345$

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