The probability that a leap year contains 52 mondays and 52 wednesdays is

$\mathrm{A} \mathrm{leap} \mathrm{year} \mathrm{has} 366\text{ days }=52weeks+2\text{ days }$

The two days can be

 $\left\{\left(sun,mon\right),\left(mon,tue\right),\left(tue, wed\right),\left(wed, thu\right),\left(thu, fri\right),\left(fri,sat\right),\left(sat,sun\right)\right\}$

$n\left(S\right)=7$

$\mathrm{A}= \mathrm{event} \mathrm{of} \mathrm{getting} 52\mathrm{mondays} \mathrm{and} 52 \mathrm{wednesdays}$

additional day is neither mon day nor wednes day

$A=\left\{\left(thu, fri\right),\left(fri,sat\right),\left(sat,sun\right)\right\}$

$, n\left(A\right)=3$

$P\left(A\right)=\frac{3}{7}$