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Q.

The probability that a leap year has 53 Sundays is


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a

1 7

b

2 7

c

3 7

d

4 7  

answer is B.

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Detailed Solution

We know that in a leap year, there are 366 days.
366 days =52 weeks +2 days
Thus, a leap year has always 52 Sundays.
The remaining 2 days can be as follows.
Sunday and Monday, Monday and Tuesday, Tuesday and Wednesday, Wednesday and Thursday, Thursday and Friday, Friday and Saturday, Saturday and Sunday.
Clearly, there are seven elementary events associated with this random experiment.
Let A be the event that a leap year has 53 Sundays.
Now, event A will happen if the last two days of the leap year are either Sunday and Monday or Saturday and Sunday.
∴ Favorable number of elementary events = 2
Hence, the required probability,
  P(A)= 2 7
Hence, the probability that a leap year has 53 Sundays is 2 7 .
Therefore, option 2 is correct.
 
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