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The probability that a non-leap year selected at random will contain $53$ Sundays from the following choices is:

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17

27

37

57

answer is A.

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Detailed Solution

Given that, a non-leap year.
We have to find the probability of non-leap year to have

53

Sundays.
A non-leap year has

365

days.
Obtain the number of weeks in a leap year. So,

3657 = 5217

Numbers of days left is

1

.
This day may be any day of the

7

days of the week, that is,
Sunday, Monday, Tuesday, Wednesday, Thursday, Friday and Saturday.
Let

A

be the event non-leap year is selected at random will contain 53 Sundays, then the probability of the event can be calculated by,

P (A) = N u m b e r of favourable outcomes T o t a l number of outcomes

= 17

The probability is

17

.
Hence, option 1) is correct.

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