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Q.

The probability that a non-leap year selected at random will have 53 Sundays is-

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a

0

b

\frac{1}{7}

c

\frac{2}{7}

d

\frac{3}{7}

answer is B.

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Detailed Solution

Days in non-leap year = 365 days
Total weeks in a year= 52
Dyas in 52 weeks
= 52 x 7
= 364 days
So, we have 1 extra day. It can be any day from the 7 days of a week. Thus, total outcome is 7.
Now we need Sunday for 53rd Sunday, Thus, favorable outcomes are 1. So, the required probability,

P = \frac{Favorable outcome}{Total outcome}

P = \frac{1}{7}

Correct option is 2.

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