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The probability that a random chosen three-digit number has exactly 3 factors is

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$\frac{2}{225}$

$\frac{7}{900}$

none of these

$\frac{1}{800}$

answer is B.

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Detailed Solution

A number has exactly 3 factors if the number is squares of a prime number.

Squares of 11, 13, 17, 19, 23, 29, 31 are 3-digit numbers.

Hence, the required probability is $\frac{7}{900}$

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