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The process that is NOT endothermic in nature is:

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${Na}_{(g)} \to {Na}_{(g)}^{+} + e^{-}$

$O_{(g)}^{-} + e^{-} \to O_{(g)}^{2 -}$

$H_{(g)} + e^{-} \to H_{(g)}^{-}$

${Ar}_{(g)} + e^{-} \to {Ar}_{(g)}^{-}$

answer is C.

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Detailed Solution

$H_{(g)} + e^{-} \to_{}^{} {H^{-}}_{(g)}$

is an exothermic process

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