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Q.

The process 2 A+BC taking place in two steps :
step 1 : 2A D and step2 : D+BC (slow), then rate of reaction gets

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a

doubled when  [B]  is doubled
 

b

quadrapled when  [a] is doubled

c

doubled when  [a] is doubled
 

d

doubled when [B] is halved
 

answer is C.

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Detailed Solution

B+DC (slow)  k=C[B][D]r=ke[B][D] 

Therefore, the correct option is (C).

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