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Q.

The product obtained in the given reaction is ${Al}_{4} C_{3} + D_{2} O \to$

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a

C₃D₄

b

C₂D₄

c

CD₄

d

C₂D₂

answer is B.

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Detailed Solution

${Al}_{4} C_{3} + 12 D_{2} O \to 3 {CD}_{4} + 4 Al (OD)_{3}$

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