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The product of (-2c) and (a – 2b + 3c) is $4 b c - 2 a c - 6 c^{2}$ .

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Detailed Solution

$(- 2 c) \times (a - 2 b + 3 c) = (- 2 c) (a) + (- 2 c) (- 2 b) + (- 2 c) (3 c) = - 2 a c + 4 b c - 6 c^{2}$

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