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The product of digits of a two-digit number is 24 such that ones place digit is 5 more than tens place digit. What is the sum of the digits of the number?

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Detailed Solution

The product of the digits of a two-digit number is 24.

Therefore, the numbers are 3,8 or 4,6 or 6,4 or 8,3.

Among these numbers, 38 is the only number whose ones place digit is 5 more than the tens place digit.

∴ Sum of digits of 38 = 3 + 8 = 11

Thus, the sum of digits of the required number is 11.

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