Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The product of divisors of N is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

N12d(N)

b

N14d(N)

c

N13d(N)

d

N15d(N)

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

N=p1n1×p2n2×p3n3×.....pnnk

The divisors of p1n1=1,p1,p12,p13,......,p1n1

The divisors of p2n2=1,p2,p22,p23,......,p2n2

The divisors of p3n3=1,p3,p32,p33,......,p3n3

The product of divisors of N

(1×p1×p12×......×p1n1)(1×p2×p22×......×p2n2)(1×p3×p32×......×p3n3)...

(p10×p11×p12×....×p1n1)(p20×p21×p22×....×p2n2)(p30×p3×p32×....×p3n3).... =(p10+1+2+......+n1)(p20+1+2+......+n2)(p30+1+2+......+n3)...

=(p1n1(n1+1)2)(p2n2(n2+1)2)(p3n3(n3+1)2).....

The number of divisors of n is n+1

=(p1n1d(N)2)(p2n2d(N)2)(p3n3d(N)2)....

=(p1n1)d(N)2(p2n2)d(N)2(p3n3)d(N)2....

=(p1n1×p2n2×p3n3....) d(N)2

=Nd(N)2

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring