The product of the following reaction is:
${Na}_{2} S + {Na}_{2} [Fe (CN)_{5} NO] \to$

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A purple coloured complex with +2 oxidation state of Fe.

A brown coloured complex with +3 oxidation state of Fe.

A brown coloured complex with +1 oxidation state of Fe.

A yellow coloured complex with +2 oxidation state of Fe.

answer is A.

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Detailed Solution

The product obtained after the reaction is ${Na}_{4} [Fe (CN)_{5} NOS]$ (purple colored).

With sodium nitroprusside solution, ionic sulfide gives a purple color in an alkaline medium.

${Na}_{2} S + {Na}_{2} [Fe (CN)_{5} NO] \to {Na}_{4} [Fe (CN)_{5} NOS]$

Here X is ${Na}_{4} [Fe (CN)_{5} (NOS)]$

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