The product of the roots of the equation  $9x^2-18\left|x\right|+5=0$ is

$9x^2-18\left|x\right|+5=0\Rightarrow 9{\left|x\right|}^2-15\left|x\right|-3\left|x\right|+5=0\Rightarrow 3\left|x\right|(3\left|x\right|-5)-1(3\left|x\right|-5)=0$$\Rightarrow (3\left|x\right|-5)(3\left|x\right|-1)=0\Rightarrow \left|x\right|=\frac{5}{3},\frac{1}{3}\Rightarrow x\pm \frac{5}{3},\pm \frac{1}{3}$

$\therefore$ Product of the roots  $=\left(\frac{5}{3}\right)(-\frac{5}{3})\left(\frac{1}{3}\right)(-\frac{1}{3})=\frac{25}{81}$