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The products formed in the first step by passing NO₂ gas into liquor ammonia till complete Neutralization, gives some gas on heating in the second step. Regarding these reactions which of the following is correct

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The gas liberated contains N₂ O

The gas liberated contains N₂

First step is disproportionation

Second step is redox reaction

answer is A, B, C, D.

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Detailed Solution

When NO₂ is passed into liquor ammonia NH₄NO₂ and NH₄NO₃ will be formed
$2 {NH}_{3} + H_{2} O + 2 {NO}_{2} \to {NH}_{4} {NO}_{3} + {NH}_{4} {NO}_{2}$

It is disproportionation reaction
$\begin{array}{l} {NH}_{4} {NO}_{3} \overset{Δ}{⟶} N_{2} O + 2 H_{2} O \\ {NH}_{4} {NO}_{2} \overset{Δ}{⟶} N_{2} + 2 H_{2} O \end{array}$
${NO}_{3}^{-} and {NO}_{2}^{-} oxidize {NH}_{4}^{+} ion$

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