The products obtained from the following chemical reactions are respectively
$(i) \underset{(hot and conc .)}{NaOH} + {Cl}_{2} ⟶ (ii) \underset{(excess)}{{XeF}_{6}} + H_{2} O ⟶$

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NaClO₃ and XeOF₄

NaOH and XeO₃

HCIO₃ and XeO₂F₂

None of these

answer is C.

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Detailed Solution

The reactions are as follows :
$(i) \underset{(hot and conc .)}{6 NaOH + 3 {Cl}_{2}} ⟶ 5 NaCl + {NaClO}_{3} + 3 H_{2} O$
$(ii) {XeF}_{6} + H_{2} O ⟶ {XeOF}_{4} + 2 HF$

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