The product(s) obtained via oxymercuration $({HgSO}_{4} + H_{2} {SO}_{4})$ of 1-butyne would be

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${CH}_{3} {CH}_{2} {COCH}_{3}$

${CH}_{3} {CH}_{2} {CH}_{2} CHO$

${CH}_{3} {CH}_{2} CHO + HCHO$

${CH}_{3} {CH}_{2} COOH + HCOOH$

answer is A.

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Detailed Solution

${CH}_{3} {CH}_{2} C \equiv CH \frac{{HgSO}_{4} H_{2} {SO}_{4}}{2 H \cdot O} {CH}_{3} {CH}_{2} C (OH)_{2} {CH}_{3} \overset{- H_{2} O}{\to} {CH}_{3} {CH}_{2} {CCH}_{3}$

1-butyne reacts with mercurous sulphide and sulfuric acid to produce isobutyl alcohol, which then passes through tautomerism to produce ethyl methyl ketone.

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