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The products obtained when this alkyl halide is subjected to E₂ reaction will be

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a

$C H_{2} = C H - C H_{2} - C H_{3}$

b

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c

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d

all of these

answer is D.

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Detailed Solution

$C H_{2} = C H - C H_{2} - C H_{3}$ (minor) and

${CH}_{3} - CH = CH - {CH}_{3}$ (major)

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