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Q.

The products of following reactions respectively are
$I. {CuSO}_{4} + {PH}_{3} ⟶ A + H_{2} {SO}_{4}$
$II. {HgCl}_{2} + {PH}_{3} ⟶ B + HCl$

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a

$\begin{array}{cc} A & B \\ {CuP}_{3} & HgP \end{array}$

b

$\begin{array}{cc} A & B \\ {Cu}_{3} P_{2} & {Hg}_{3} P_{2} \end{array}$

c

$\begin{array}{cc} A & B \\ CuP & HgP \end{array}$

d

$\begin{array}{cc} A & B \\ {CuP}_{3} & {Hg}_{3} P_{2} \end{array}$

answer is B.

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Detailed Solution

$3 {CuSO}_{4} + 2 {PH}_{3} ⟶ {Cu}_{3} P_{2} + 3 H_{2} {SO}_{4}$
$3 {HgCl}_{2} + 2 {PH}_{3} ⟶ {Hg}_{3} P_{2} + 6 HCl$

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